Correct answer: Be21...Ng2/Nd3[a]/Nc2 2.f3#[A] 1...Nf8/[б]//Ng5[c]/Ng7/[б]//Nd4/[б]//Nd8/[б]//Nc5/[б]//Nc7/[б]/ 2.Qd4#[Б] 1...Bd5 2.Q:d5# 1...Nf4
