Correct answer: Qd21...Nf3[a]/Nc6 2.Q:g7#[Б] 1...N:f5/[б]/ 2.Qe5#[A] 1...Ne2/Nc2/Nb3/Nb5 2.Qe5#[A]/Q:g7#[Б] 1.Qe3? (2.Qg5#) 1...Nf3[a] 2.<
