Correct answer: Ba21...e:d4[a] 2.Nfd6#[A] 1...Bg5/Be7/Bd8 2.Ng3# 1...Bh4 2.R:h4# 1...e2 2.Nd2# 1.Qf7? (2.Ncd6#[Б]/Nfd6#[A]) 1...R:c3[c] 2.Ncd6#
