Correct answer: Qc41...c6[a] 2.Qe5#[A] 1...c5/[б]/ 2.Qd7#[Б] 1...Bc6 2.Qb4#/Qe5#[A] 1...Bd5 2.Q:d5# 1.Qb6+?? 1...c6[a] 2.Qd4#[C] 1...Bc6 2.Qb4# but 1.
