Correct answer: Ra51...e6[a]/e5/[б]/ 2.Q:d7#[A] 1...d6[c]/d5[d] 2.Q:e7#[Б] 1.Ra6? (2.Rh6#) 1...e6[a] 2.Q:d7#[A] 1...d6[c] 2.Q:e7#[Б] but 1...c:d2! 1.Qb6? (2.Qg6#/Q