Correct answer: Ba41...R:f5[a]/Rg3/[б]//Rg2[c]/Rg1[c]/Rh4[c] 2.Rc4#[Б] 1...K:f4 2.Rd4#[A] 1...f2 2.Qe3# 1.Bc2? zz 1...R:f5[a] 2.Rc4#[Б]/B:d3#[C]
