Correct answer: Qa51.Nb:d6[A]? (2.Ne4#/Nb7#) 1...Nc2[a]/N:c4/[б]/ 2.Qa5#[Б] but 1...d3! 1.Qa5[Б]! (2.Q:a3#) 1...Nb1/Nc2[a]/Na:c4/[б]/ 2.Nb:d6#[
