Correct answer: Qh71.Qb8+? 1...Kf3[a] 2.Qf4#[A] 1...Kh4/[б]/ 2.Qh2#[D] but 1...Kh3! 1.Qa2? zz 1...Kf3[a] 2.Qg2#[Б] 1...Kh4/[б]/ 2.Qh2#[D] but 1.
