Correct answer: Nf51...Nf3[a]/Nf5/[б]//Nc2[a]/Nc6[a]/Nb3[a]/Nb5[a] 2.Rg4#[A] 1.B:d4? (2.d3#[Б]/Rg4#[A]) 1...Nf6 2.d3#[Б] but 1...c:d4! 1.Bc1?? (2.d3#[Б])