Correct answer: Qc31...Nb2[a]/Nb6[a]/Nc3/Nc5[a] 2.Nc3#[A] 1...Rd8/[б]/ 2.Q:e6#[Б] 1...N:d4[c] 2.Nb4#[C] 1...Nd8/Ne5[d]/Ne7/Nb4/Nb8/Na5[d]/<
