Correct answer: Nb31...c5[a]/Bd3/Bb3/Ba2 2.Qd7#[Б] 1...Ke6/e:f6/[б]//e5[d] 2.Bg8#[A] 1...e6[c] 2.Be4#[C] 1.Bf4? (2.Nc7#[D]) 1...c5[a] 2.Qd7#[Б] 1...Ke6/e5
