Correct answer: Qd11...R:d6[a] 2.Rc5#[A] 1...e:d6/[б]/ 2.Nb4#[Б] 1...e6 2.Rc7# 1...c3 2.Q:c3# 1.R:h6? (2.Rc5#[A]/Nb4#[Б]) 1...e:d3/e:d6/[б]/ 2.Rc5#[A] but 1...e6! 1
