Correct answer: Ne21...Nb4[a]/Nb8[a]/Nc7[a] 2.N:c5#[A] 1...Ng1/[б]//Ng5/[б]//Nf2/[б]/ 2.N:f4#[Б] 1...b4 2.B:c4# 1.Nb3? zz 1...Nb4[a]/Nb8[a]/Nc7[a
