Correct answer: Nd21...Bd5 2.Nd7#[A] 1.Nc3? (2.Rf5#) 1...Rh5[a] 2.Nc4#[D] 1...Be4/[б]/ 2.Nc4#[D]/Nd7#[A] 1...Bd7[c] 2.N:d7#[A] 1...Rf4 2.R