Correct answer: Qb31...e:d2[a]/e2 2.Bf2# 1...c:d2[a]/c2 2.Qa1# 1.Qc2? (2.Q:c3#/d:c3#) 1...c:d2[a] 2.Nf5#[C] 1...e:d2[a] 2.Bf2# 1...Ne2/[б]/ 2.Qd3#[A] 1...Qa5[c]
