Correct answer: Qf51...N:f2[a]/Nf6[a]/Ng3[a]/Ng5[a]/Nc3[a] 2.Qc3#[A] 1...Nc5/[б]/ 2.Qh8#[Б] 1...Qe3 2.f:e3# 1.Qb7? (2.Q:d5#) 1...N:f2[a]/Nf6[a]/<
