Correct answer: Rf11...Kf5[a] 2.Qd3#[A]/Qd5#[Б]/R:f4#[C] 1...Q:d8/[б]//Qe7 2.R:f4#[C] 1...B:f3[c]/g:f3[c]/e2[c] 2.Qd3#[A] 1...c4[d] 2.Qd5#[Б] 1...Qf7/Qf5/Q