Correct answer: R:f31...e5[a] 2.Nf5#[A] 1...c:b3/[б]//c3[c] 2.Q:d3#[Б] 1...f2 2.Ne2#[C] 1.Ka2? zz 1...e5[a] 2.Nf5#[A] 1...c3[c] 2.Q:d3#[Б] 1...f2 2.Ne2#[C] but 1...c:b3+/[б]/!