Correct answer: f41...Bh6[a] 2.N:e7#[A] 1...Ncd2/[б]//Nd6/[б]//Ne3/[б]//Ne5[c]/Nb2/Nb6/Na3/Nca5 2.Ne3#[Б] 1...Nc1/N:c5/Nbd2/Nd4/Na1/