Correct answer: Ne51...Ng6[a] 2.Rgf7#[A] 1...Ne6/[б]/ 2.Ref7#[Б] 1...g:f3 2.Q:f3# 1.Ng5? (2.Qf1#) 1...Ng6[a] 2.Nh7#[C] 1...Ne6/[б]/ 2.R:e6#[D] but 1...c
