Correct answer: Qg71...K:e5[a] 2.Qg7#[A] 1...Rd5/[б]//Rd7/[б]//Rd8/[б]/ 2.N:c6#[Б] 1...f:g4[c] 2.N:e6#[C] 1.Qe7? (2.Q:d6#) 1...K:e5[a] 2.Qg7#[A] 1...R<