Correct answer: Bc21...e:f5[a] 2.Qh6#[A] 1.g4? (2.Qd8#[Б]/Qh6#[A]) 1...e:f5[a]/Rd4[d] 2.Qh6#[A] 1...Re3[c]/Rf4[c] 2.Qd8#[Б] but 1...R:g4/[б]/! 1.Bc2[C]!
