Correct answer: Ng41...Ncd7[a]/Nb3/Na6 2.Qc3#[A] 1...e5/[б]/ 2.Nf5#[Б] 1...Bb8 2.Q:c5# 1...Nd3 2.c3#/Qc3#[A] 1...Ng4/N:g8/Nh5/Nh7/Nfd7 2.Q