Correct answer: Qf41...Bh2[a]/Bf2[a] 2.Bf2#[A] 1...Be3/[б]/ 2.Qc3#[Б] 1...c:d3[c] 2.Q:d3#[C] 1...d:e4[d] 2.d:c4#[D] 1...Ne6/Nf7/Nc6/Nb7 2.Nc6# 1...c3 2.Nb3#
