Correct answer: Qe21...Kf5[a] 2.Qd5#[A] 1...f3/[б]/ 2.Rc5#[Б] 1.Qd2? zz 1...Kf5[a] 2.Q:f4#[D] 1...f3/[б]/ 2.Qa5#[E] 1...Kd5[d]/f5[c] 2.Q:d4#[C] but 1...K:e4
