Correct answer: Rh31...Nc3[a] 2.Qc5#[A] 1...Nd2/Na3 2.Qb2#[Б] 1.Bc2? (2.Re4#) 1...Nc3[a] 2.Qc5#[A] 1...Nd2 2.Qb2#[Б] but 1...B:e5/[б]/! 1.R