Correct answer: Rd51...Rd1[a]/Rec1/Rb1/Ra1/R:f1 2.Qe7#[A] 1...Rb2/Ra2/Rd2/[б]//Rce2/Rf2/Rg2/Rh2 2.Rc7#[Б] 1...Ne4 2.Qh3#/Bh3#[C
