Correct answer: Nc41...Ke4[a] 2.Bf3#[A] 1...Ke6/[б]/ 2.Bf7#[Б] 1.Bh8? zz 1...Ke4[a] 2.Bf3#[A] 1...Ke6/[б]/ 2.Bf7#[Б] but 1...c4! 1.Ka4? zz 1...K
