Correct answer: Qc31...K:f5[a] 2.Qf7#[A] 1...B:f5+/[б]/ 2.d7#[Б] 1.Q:b7? (2.Qf3#) 1...K:f5[a] 2.Qf7#[A] 1...B:f5+/[б]/ 2.Re6#[D] 1...Be2/Be4[c] 2.Q<