Correct answer: Bc21...Ke1[a]/Be2/[б]/ 2.Qe2#[A] 1...Bd3[c] 2.Qf4#[Б] 1.Ba4? zz 1...Ke1[a] 2.Qe3#[C] 1...Bd3[c] 2.Rd1#[D] but 1...Be2/[б]/! 1.R