Correct answer: Rd71...Kd4[a] 2.R:d6#[A] 1...Kc6/[б]/ 2.Q:c5#[Б] 1...Ne4/Nf1/Nf3/Nc4/Nb1 2.Q:e4# 1.B:b3+?? 1...Kd4[a] 2.Q:d2#/R:d6#[A]
