Correct answer: Nf31...g4[a] 2.Qc5#[A] 1...Be4/[б]//Ba2 2.B:e4#[Б] 1...Ng4 2.Q:b1# 1.Qg2? (2.Qf3#) 1...g4[a] 2.Qd5#[C] 1...Be4/[б]/ 2.Q:e4#[D] but 1...e
