Correct answer: Rf31...Bg3/Bh2[a]/Bc7[a]/Bb8[a] 2.Nc3#[A] 1...Bf6/Bg7/[б]//Bh8/[б]//Bd4/Bb2/[б]//Ba1/[б]/ 2.Nd6#[C] 1...Bf4 2.Nc3#[A]/Nf6#[Б]
