Correct answer: Nf31...Bf3/Rg4[a]/Rg5/[б]//Rg7[a]/Rg8[a] 2.Nd3#[A] 1...Rf3[c]/Re3[d] 2.Ng6#[Б] 1...Rg6/Rd3 2.N:g6#[Б]/Nd3#[A] 1.Qe1? (2.f:g3#)