Correct answer: Qb51...Ng1[a]/Ng5[a]/Nh2[a]/Ne1/[б]//Ne5[c]/Nd2[d]/Nd4[e] 2.Rd4#[A] 1...f:e4[f] 2.Be6#[Б] 1...Nc6[g] 2.Qe6#[C] 1...Nd7[h]/Na6[i] 2.Q