Correct answer: Qf51...Ne6[a]/Nf7/[б]//Nb7[d] 2.Nb7#[C] 1...N:c6[c] 2.Q:c6#[D] 1...Nb4[e]/Nb8[f]/Nc7[h] 2.Q:b4#[E] 1...Nc5[g] 2.Qb8#[F] 1...Rd2/R