Correct answer: Qb71...f5[a] 2.Qh8#[A] 1...Bb6/[б]//Ba7[c] 2.N:b3#[Б] 1...e3[d] 2.Qg4#[C] 1.Qc6? zz 1...Bb6/[б]/ 2.Q:b6#[E]/N:b3#[Б] 1...Ba7[c] 2.N:b3#[Б]
