Correct answer: Nf31...e2[a] 2.R:e2#[A] 1...Nc2/[б]//Nd3[c]/Nd5[d]/Na2[e]/Na6[e] 2.Qd3#[Б] 1...Ng1[f]/Ng5[f]/Nf2[g] 2.R:f4#[C] 1...c:d4[h] 2.Qf3#[D] 1...e6 2.