Correct answer: Ba71...d:c2/d:e2[a] 2.Qd2#[A] 1...d:e4/[б]/ 2.Qd8#[Б] 1...b4[c] 2.Q:c5#[C] 1...Bc1/Bc3/Ba3[d] 2.Qc3#[E] 1...d2 2.Rc:d2#/Q:d2#[A] 1...f5 2.Be5# 1...N<