Correct answer: Qf51...R:d4[a] 2.Q:d4#[A] 1...Nf3/[б]//Ng2[c]/Nc2[e] 2.Q:f3#[Б] 1...Nd3[d] 2.Rde2#[C] 1...B:f4[f] 2.Rfe2#[D] 1...Rb5/Rb6/Rb7/Rb8
