Correct answer: Qg71...f3 2.d:e3#/Q:e3# 1.Ndf2? (2.Bb3#[Б]/R:a4#[A]) 1...R:e4[a] 2.N:e4# 1...c1Q/c1R/b1Q/b1R/Rc3/Rb3/R:a3 2.Bb3#[Б] but
