Correct answer: Qg21...Ke3[a] 2.Qc1#[A] 1...Ke5/[б]/ 2.Qc7#[Б] 1.Qc1+[A]?? 1...Ke5/[б]/ 2.Qc7#[Б] but 1...Kg4! 1.Qc7+[Б]?? 1...Ke3[a] 2.Qc1#[A]