Correct answer: Bc41...f3[a]/g3[d] 2.N:f3#[A] 1...Ne6/[б]//N8f7[c]/Nc6[c]/N8b7/[б]/ 2.N:e6#[Б] 1...Ne4[e]/Ne8[f]/Nf5[f]/N6f7[f]/Nc4[g]/Nc8[f]/Nb5[h]/N