Correct answer: Nb51...a3[a] 2.B:b3#[A] 1...Ng4/[б]//Nh1/[б]//Nh3/[б]//Ne4/[б]//Nd1/[б]//Nd3/[б]/ 2.Qd3#[Б] 1...c:b4[c] 2.Rc6#[C] 1.Rb5? zz 1...a3[a] 2.B:b3#[A
