Correct answer: b31...a:b6[a] 2.Rd5#[A] 1...R:c4/[б]/ 2.Nd3#[Б] 1...R:d6[c] 2.R:b5#[C] 1...b:c4[d] 2.N:d7#[D] 1...Rd4 2.e:d4# 1.Kc7[E]? (2.Rd5#[A]/R:b5#[C]) 1...a
