Correct answer: Nd41...Nc6[a]/Nc8[a] 2.R:c6#[A] 1...Ne7/[б]//Nf6/[б]//Nc7/[б]//Nb6/[б]/ 2.Rd3#[Б] 1...N:b4[c] 2.B:b4#[C] 1.Bc1? zz 1...Nc6[a]/Nc8