Correct answer: Qa61...Bg4[a]/Bc2/[б]//Bb3/Ba4[c] 2.Q:g4#[A] 1...d:c4[d] 2.Qd7#[Б] 1.Ne1? zz 1...Be2[e]/Bg4[a]/Bh5[f] 2.Nc2#[E] 1...Bf3/Bc2/[б