Correct answer: Rg21...Ng3[a]/Ng7[a]/Nf6[a] 2.B:f4#[A] 1...d4/[б]/ 2.Nc4#[Б] 1...Nc3[c]/Nd2[d]/Na3[d] 2.Qd2#[C] 1...Re2/Rd1/Rc1/Rf1/Rg1/Rh1
