Correct answer: Kh51...Nd4[a] 2.Bf4#[A] 1...Nd3/[б]/ 2.Re4#[C] 1...Ne2[c] 2.Bf2#[D] 1...Nd8/Ne7/Na5/Na7 2.Q:b6#[Б] 1...e4 2.Q:e4# 1.Be4? (2.N