Correct answer: Q:d21...d:e2[a] 2.Qc2#[A] 1...N:e2/[б]//Nb3/[б]//Na2/[б]/ 2.Qb3#[Б] 1...Bf2[c]/Bg3[c]/Bh4[c] 2.N:d2#[C] 1...b3 2.Na3# 1.Q:d2! zz 1...d: